What is (\partial)/(\partial x)(cos(5x-2y^2)) ?

The answer to (\partial)/(\partial x)(cos(5x-2y^2)) is -sin(5x-2y^2)*5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(cos(5x-2y^2))

\frac{\partial}{\partial x} (cos (5 x - 2 y^{2}))

- sin (5 x - 2 y^{2}) \cdot 5

Solution steps

\frac{\partial}{\partial x} (cos (5 x - 2 y^{2}))

Treat

y

as a constant

Apply the chain rule:

- sin (5 x - 2 y^{2}) \frac{\partial}{\partial x} (5 x - 2 y^{2})

= - sin (5 x - 2 y^{2}) \frac{\partial}{\partial x} (5 x - 2 y^{2})

\frac{\partial}{\partial x} (5 x - 2 y^{2}) = 5

= - sin (5 x - 2 y^{2}) \cdot 5

What is (\partial)/(\partial x)(cos(5x-2y^2)) ?
The answer to (\partial)/(\partial x)(cos(5x-2y^2)) is -sin(5x-2y^2)*5