What is the tangent of f(x)=2x^2+3x,\at x=-2 ?

The tangent of f(x)=2x^2+3x,\at x=-2 is y=-5x-8

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tangent of f(x)=2x^2+3x,\at x=-2

tangent of

f (x) = 2 x^{2} + 3 x, at x = - 2

y = - 5 x - 8

Solution steps

Find the tangent point:

(- 2, 2)

Find the slope of

f (x) = 2 x^{2} + 3 x : \frac{df ( x )}{d x} = 4 x + 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 5

Find the line with slope m=

- 5

and passing through

(- 2, 2) : y = - 5 x - 8

y = - 5 x - 8

What is the tangent of f(x)=2x^2+3x,\at x=-2 ?
The tangent of f(x)=2x^2+3x,\at x=-2 is y=-5x-8