What is the solution for (y^2+9)dx-1/((2x+1)^2)dy=0 ?

The solution for (y^2+9)dx-1/((2x+1)^2)dy=0 is y=3tan(4x^3+6x^2+3x-c_{1})

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(y^2+9)dx-1/((2x+1)^2)dy=0

(y^{2} + 9) d x - \frac{1}{( 2 x + 1 ) ^{2}} d y = 0

y = 3 tan (4 x^{3} + 6 x^{2} + 3 x - c_{1})

Solution steps

(y^{2} + 9) d x - \frac{1}{( 2 x + 1 ) ^{2}} d y = 0

Solve separable ODE:

y = 3 tan (4 x^{3} + 6 x^{2} + 3 x - c_{1})

y = 3 tan (4 x^{3} + 6 x^{2} + 3 x - c_{1})

What is the solution for (y^2+9)dx-1/((2x+1)^2)dy=0 ?
The solution for (y^2+9)dx-1/((2x+1)^2)dy=0 is y=3tan(4x^3+6x^2+3x-c_{1})