What is area x=y^2+14y+16,x=7y+6 ?

The answer to area x=y^2+14y+16,x=7y+6 is No Solution

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

area x=y^2+14y+16,x=7y+6

area

x = y^{2} + 14 y + 16, x = 7 y + 6

No Solution

Solution steps

Isolate

y

for

x = y^{2} + 14 y + 16 : y = - 7 + x + 33, y = - x + 33 - 7

Isolate

y

for

x = 7 y + 6 : y = \frac{x - 6}{7}

f_{1} (x) = - 7 + x + 33

f_{2} (x) = - x + 33 - 7

To find the intersection points solve

f_{i} (x) = f_{j} (x)

- 7 + x + 33 = - x + 33 - 7 : x = - 33

- 7 + x + 33 = \frac{x - 6}{7} : x = - 8, x = - 29

- x + 33 - 7 = \frac{x - 6}{7} :

No Solution for

x \in R

Curves not bounded

= No Solution

What is area x=y^2+14y+16,x=7y+6 ?
The answer to area x=y^2+14y+16,x=7y+6 is No Solution