What is the integral of e^{x^3+1} ?

The integral of e^{x^3+1} is e(-(x\Gamma(1/3 ,-x^3))/(3\sqrt[3]{-x^3)})+C

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integral of e^{x^3+1}

\int e^{x^{3} + 1} d x

Solution steps

\int e^{x^{3} + 1} d x

e^{x^{3} + 1} = e^{1} e^{x^{3}}

= \int e^{1} e^{x^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{1} \cdot \int e^{x^{3}} d x

Simplify

= e \cdot \int e^{x^{3}} d x

Use the nonelementary integral:

Add a constant to the solution

What is the integral of e^{x^3+1} ?
The integral of e^{x^3+1} is e(-(x\Gamma(1/3 ,-x^3))/(3\sqrt[3]{-x^3)})+C