What is the derivative of f(x)=2x^4+3x+16 ?

The derivative of f(x)=2x^4+3x+16 is 8x^3+3

What is the first derivative of f(x)=2x^4+3x+16 ?

The first derivative of f(x)=2x^4+3x+16 is 8x^3+3

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derivative of

f (x) = 2 x^{4} + 3 x + 16

8 x^{3} + 3

Solution steps

\frac{d}{d x} (2 x^{4} + 3 x + 16)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{4}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (16)

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (16) = 0

= 8 x^{3} + 3 + 0

Simplify

= 8 x^{3} + 3

What is the derivative of f(x)=2x^4+3x+16 ?
The derivative of f(x)=2x^4+3x+16 is 8x^3+3
What is the first derivative of f(x)=2x^4+3x+16 ?
The first derivative of f(x)=2x^4+3x+16 is 8x^3+3