What is area y=-x^2+7x,y=x^2-3x ?

The answer to area y=-x^2+7x,y=x^2-3x is 125/3

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area y=-x^2+7x,y=x^2-3x

area

y = - x^{2} + 7 x, y = x^{2} - 3 x

\frac{125}{3}

Decimal

41.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{5} - x^{2} + 7 x - (x^{2} - 3 x) d x

Solve

\int_{0}^{5} - x^{2} + 7 x - (x^{2} - 3 x) d x : \frac{125}{3}

The area is:

= \frac{125}{3}

What is area y=-x^2+7x,y=x^2-3x ?
The answer to area y=-x^2+7x,y=x^2-3x is 125/3