What is expand ((x^{(3)}-1)(x+1)^{(3)})/(x+2) ?

The solution to expand ((x^{(3)}-1)(x+1)^{(3)})/(x+2) is (x^6+3x^5+3x^4-3x^2-3x-1)/(x+2)

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expand ((x^{(3)}-1)(x+1)^{(3)})/(x+2)

expand

\frac{( x ^{(3)} - 1 ) ( x + 1 ) ^{(3)}}{x + 2}

\frac{x ^{6} + 3 x ^{5} + 3 x ^{4} - 3 x ^{2} - 3 x - 1}{x + 2}

Solution steps

\frac{( x ^{3} - 1 ) ( x + 1 ) ^{3}}{x + 2}

(x + 1)^{3} = x^{3} + 3 x^{2} + 3 x + 1

= \frac{( x ^{3} - 1 ) ( x ^{3} + 3 x ^{2} + 3 x + 1 )}{x + 2}

Expand

(x^{3} - 1) (x^{3} + 3 x^{2} + 3 x + 1) : x^{6} + 3 x^{5} + 3 x^{4} - 3 x^{2} - 3 x - 1

= \frac{x ^{6} + 3 x ^{5} + 3 x ^{4} - 3 x ^{2} - 3 x - 1}{x + 2}

What is expand ((x^{(3)}-1)(x+1)^{(3)})/(x+2) ?
The solution to expand ((x^{(3)}-1)(x+1)^{(3)})/(x+2) is (x^6+3x^5+3x^4-3x^2-3x-1)/(x+2)