What is the tangent of x/(1+x^2),\at x=1 ?

The tangent of x/(1+x^2),\at x=1 is y= 1/2

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tangent of x/(1+x^2),\at x=1

tangent of

\frac{x}{1 + x ^{2}}, at x = 1

y = \frac{1}{2}

Solution steps

Find the tangent point:

(1, \frac{1}{2})

Find the slope of

y = \frac{x}{1 + x ^{2}} : \frac{d y}{d x} = \frac{1 - x ^{2}}{( 1 + x ^{2} ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(1, \frac{1}{2}) : y = \frac{1}{2}

y = \frac{1}{2}

What is the tangent of x/(1+x^2),\at x=1 ?
The tangent of x/(1+x^2),\at x=1 is y= 1/2