What is the solution for (dy)/(dx)=(y^2x)/(x^2+1) ?

The solution for (dy)/(dx)=(y^2x)/(x^2+1) is y=-2/(ln(x^2+1)+c_{1)}

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(dy)/(dx)=(y^2x)/(x^2+1)

\frac{d y}{d x} = \frac{y ^{2} x}{x ^{2} + 1}

y = - \frac{2}{ln ( x ^{2} + 1 ) + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{y ^{2} x}{x ^{2} + 1}

Solve separable ODE:

y = - \frac{2}{ln ( x ^{2} + 1 ) + c _{1}}

y = - \frac{2}{ln ( x ^{2} + 1 ) + c _{1}}

What is the solution for (dy)/(dx)=(y^2x)/(x^2+1) ?
The solution for (dy)/(dx)=(y^2x)/(x^2+1) is y=-2/(ln(x^2+1)+c_{1)}