What is area 3x^2+3x-8,2x^2+x+7 ?

The answer to area 3x^2+3x-8,2x^2+x+7 is 256/3

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area 3x^2+3x-8,2x^2+x+7

area

3 x^{2} + 3 x - 8, 2 x^{2} + x + 7

\frac{256}{3}

Decimal

85.33333 \dots

Solution steps

Apply the area formula:

\int_{- 5}^{3} 3 x^{2} + 3 x - 8 - (2 x^{2} + x + 7) d x

Solve

\int_{- 5}^{3} 3 x^{2} + 3 x - 8 - (2 x^{2} + x + 7) d x : \frac{256}{3}

The area is:

= \frac{256}{3}

What is area 3x^2+3x-8,2x^2+x+7 ?
The answer to area 3x^2+3x-8,2x^2+x+7 is 256/3