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Popular Calculus >

integral from 0 to 1 of (1-x^3)

Solution

\int_{0}^{1} (1 - x^{3}) d x

Solution

\frac{3}{4}

+1

Decimal

0.75

Solution steps

\int_{0}^{1} 1 - x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 1 d x - \int_{0}^{1} x^{3} d x

\int_{0}^{1} 1 d x = 1

\int_{0}^{1} x^{3} d x = \frac{1}{4}

= 1 - \frac{1}{4}

Simplify

1 - \frac{1}{4} : \frac{3}{4}

= \frac{3}{4}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (1-x^3) ?
The integral from 0 to 1 of (1-x^3) is 3/4