What is the limit as x approaches 0+of x(ln(x^2)) ?

The limit as x approaches 0+of x(ln(x^2)) is 0

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limit as x approaches 0+of x(ln(x^2))

x \to 0 + lim (x (ln (x^{2})))

0

Solution steps

x \to 0 + lim (x ln (x^{2}))

Rewrite for L'Hopital

= x \to 0 + lim (\frac{ln ( x ^{2} )}{\frac{1}{x}})

Apply L'Hopital's Rule

= x \to 0 + lim (\frac{\frac{2}{x}}{- \frac{1}{x ^{2}}})

Simplify

\frac{\frac{2}{x}}{- \frac{1}{x ^{2}}} : - 2 x

= x \to 0 + lim (- 2 x)

Plug in the value

x = 0

= - 2 \cdot 0

Simplify

= 0

What is the limit as x approaches 0+of x(ln(x^2)) ?
The limit as x approaches 0+of x(ln(x^2)) is 0