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Popular Calculus >

integral of 1/(2y^2)

Solution

\int \frac{1}{2 y ^{2}} d y

Solution

- \frac{1}{2 y} + C

Solution steps

\int \frac{1}{2 y ^{2}} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{y ^{2}} d y

Apply the Power Rule

= \frac{1}{2} (- \frac{1}{y})

Simplify

\frac{1}{2} (- \frac{1}{y}) : - \frac{1}{2 y}

= - \frac{1}{2 y}

Add a constant to the solution

= - \frac{1}{2 y} + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of 1/(2y^2) ?
The integral of 1/(2y^2) is -1/(2y)+C