What is the derivative of (1/(y^2)-7/(y^4))(y-5y^3) ?

The derivative of (1/(y^2)-7/(y^4))(y-5y^3) is (21)/(y^4)-(36)/(y^2)-5

What is the first derivative of (1/(y^2)-7/(y^4))(y-5y^3) ?

The first derivative of (1/(y^2)-7/(y^4))(y-5y^3) is (21)/(y^4)-(36)/(y^2)-5

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derivative of

(\frac{1}{y ^{2}} - \frac{7}{y ^{4}}) (y - 5 y^{3})

\frac{21}{y ^{4}} - \frac{36}{y ^{2}} - 5

Solution steps

\frac{d}{d y} ((\frac{1}{y ^{2}} - \frac{7}{y ^{4}}) (y - 5 y^{3}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = \frac{1}{y ^{2}} - \frac{7}{y ^{4}}, g = y - 5 y^{3}

= \frac{d}{d y} (\frac{1}{y ^{2}} - \frac{7}{y ^{4}}) (y - 5 y^{3}) + \frac{d}{d y} (y - 5 y^{3}) (\frac{1}{y ^{2}} - \frac{7}{y ^{4}})

\frac{d}{d y} (\frac{1}{y ^{2}} - \frac{7}{y ^{4}}) = - \frac{2}{y ^{3}} + \frac{28}{y ^{5}}

\frac{d}{d y} (y - 5 y^{3}) = 1 - 15 y^{2}

= (- \frac{2}{y ^{3}} + \frac{28}{y ^{5}}) (y - 5 y^{3}) + (1 - 15 y^{2}) (\frac{1}{y ^{2}} - \frac{7}{y ^{4}})

Simplify

(- \frac{2}{y ^{3}} + \frac{28}{y ^{5}}) (y - 5 y^{3}) + (1 - 15 y^{2}) (\frac{1}{y ^{2}} - \frac{7}{y ^{4}}) : \frac{21}{y ^{4}} - \frac{36}{y ^{2}} - 5

= \frac{21}{y ^{4}} - \frac{36}{y ^{2}} - 5

What is the derivative of (1/(y^2)-7/(y^4))(y-5y^3) ?
The derivative of (1/(y^2)-7/(y^4))(y-5y^3) is (21)/(y^4)-(36)/(y^2)-5
What is the first derivative of (1/(y^2)-7/(y^4))(y-5y^3) ?
The first derivative of (1/(y^2)-7/(y^4))(y-5y^3) is (21)/(y^4)-(36)/(y^2)-5