What is the derivative of (x^2-2x-8)/(x+2) ?

The derivative of (x^2-2x-8)/(x+2) is 1

What is the first derivative of (x^2-2x-8)/(x+2) ?

The first derivative of (x^2-2x-8)/(x+2) is 1

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derivative of

\frac{x ^{2} - 2 x - 8}{x + 2}

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 2 x - 8}{x + 2})

Simplify

\frac{x ^{2} - 2 x - 8}{x + 2} : x - 4

= \frac{d}{d x} (x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (4)

\frac{d x}{d x} = 1

\frac{d}{d x} (4) = 0

= 1 - 0

Simplify

= 1

What is the derivative of (x^2-2x-8)/(x+2) ?
The derivative of (x^2-2x-8)/(x+2) is 1
What is the first derivative of (x^2-2x-8)/(x+2) ?
The first derivative of (x^2-2x-8)/(x+2) is 1