What is the tangent of 2/(1-t),\at t=-2 ?

The tangent of 2/(1-t),\at t=-2 is y= 2/9 t+10/9

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tangent of 2/(1-t),\at t=-2

tangent of

\frac{2}{1 - t}, at t = - 2

y = \frac{2}{9} t + \frac{10}{9}

Solution steps

Find the tangent point:

(- 2, \frac{2}{3})

Find the slope of

y = \frac{2}{1 - t} : \frac{d y}{d t} = \frac{2}{( 1 - t ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{2}{9}

Find the line with slope m=

\frac{2}{9}

and passing through

(- 2, \frac{2}{3}) : y = \frac{2}{9} t + \frac{10}{9}

y = \frac{2}{9} t + \frac{10}{9}

What is the tangent of 2/(1-t),\at t=-2 ?
The tangent of 2/(1-t),\at t=-2 is y= 2/9 t+10/9