Solution
Solution
Solution steps
Solve separable ODE:
Graph
Popular Examples
xyy^'+4x^2+y^2=02xdz-2zdx=sqrt(x^2+4z^2)dxintegral of 1/((x+8)(x^2+16))integral of sin(4x+5)integral of sin^2(t)cos^4(t)
Frequently Asked Questions (FAQ)
What is the solution for 2xdy+ydx=0 ?
The solution for 2xdy+ydx=0 is y=(c_{1})/(sqrt(x))