What is the solution for f^'(x)=(8x^5-6x^9)/(x^4) ?

The solution for f^'(x)=(8x^5-6x^9)/(x^4) is f(x)=4x^2-x^6+c_{1}

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f^'(x)=(8x^5-6x^9)/(x^4)

f^{^{'}} (x) = \frac{8 x ^{5} - 6 x ^{9}}{x ^{4}}

f (x) = 4 x^{2} - x^{6} + c_{1}

Solution steps

f^{'} (x) = \frac{8 x ^{5} - 6 x ^{9}}{x ^{4}}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int \frac{8 x ^{5} - 6 x ^{9}}{x ^{4}} d x

\int \frac{8 x ^{5} - 6 x ^{9}}{x ^{4}} d x = 4 x^{2} - x^{6} + c_{1}

f (x) = 4 x^{2} - x^{6} + c_{1}

What is the solution for f^'(x)=(8x^5-6x^9)/(x^4) ?
The solution for f^'(x)=(8x^5-6x^9)/(x^4) is f(x)=4x^2-x^6+c_{1}