What is the integral of (x+1)sin(3x) ?

The integral of (x+1)sin(3x) is -1/3 cos(3x)(x+1)+1/9 sin(3x)+C

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integral of (x+1)sin(3x)

\int (x + 1) sin (3 x) d x

- \frac{1}{3} cos (3 x) (x + 1) + \frac{1}{9} sin (3 x) + C

Solution steps

\int (x + 1) sin (3 x) d x

Apply Integration By Parts

= - \frac{1}{3} cos (3 x) (x + 1) - \int - \frac{1}{3} cos (3 x) d x

\int - \frac{1}{3} cos (3 x) d x = - \frac{1}{9} sin (3 x)

= - \frac{1}{3} cos (3 x) (x + 1) - (- \frac{1}{9} sin (3 x))

Simplify

= - \frac{1}{3} cos (3 x) (x + 1) + \frac{1}{9} sin (3 x)

Add a constant to the solution

= - \frac{1}{3} cos (3 x) (x + 1) + \frac{1}{9} sin (3 x) + C

What is the integral of (x+1)sin(3x) ?
The integral of (x+1)sin(3x) is -1/3 cos(3x)(x+1)+1/9 sin(3x)+C