derivative 1+12sqrt(t)

Lösung

ableitung von

1 + 12 t

\frac{6}{t}

Schritte zur Lösung

\frac{d}{d t} (1 + 12 t)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) + \frac{d}{d t} (12 t)

\frac{d}{d t} (1) = 0

\frac{d}{d t} (12 t) = \frac{6}{t}

= 0 + \frac{6}{t}

Vereinfache

= \frac{6}{t}

\frac{d y}{d x} - 2 y = 1 - 2 x

a \to - 2 lim (a^{2} + 3 m - 1)

x \to 0 lim (\frac{8 x ^{2} - 2 x}{2 x})

\int (2 x - x)^{2} d x

\int_{0}^{4} y d y