What is the derivative of (3x/(x+1)) ?

The derivative of (3x/(x+1)) is 3/((x+1)^2)

What is the first derivative of (3x/(x+1)) ?

The first derivative of (3x/(x+1)) is 3/((x+1)^2)

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\frac{d}{d x} (\frac{3 x}{x + 1})

\frac{3}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x}{x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{x}{x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 3 \cdot \frac{\frac{d x}{d x} ( x + 1 ) - \frac{d}{d x} ( x + 1 ) x}{( x + 1 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x + 1) = 1

= 3 \cdot \frac{1 \cdot ( x + 1 ) - 1 \cdot x}{( x + 1 ) ^{2}}

Simplify

3 \cdot \frac{1 \cdot ( x + 1 ) - 1 \cdot x}{( x + 1 ) ^{2}} : \frac{3}{( x + 1 ) ^{2}}

= \frac{3}{( x + 1 ) ^{2}}

What is the derivative of (3x/(x+1)) ?
The derivative of (3x/(x+1)) is 3/((x+1)^2)
What is the first derivative of (3x/(x+1)) ?
The first derivative of (3x/(x+1)) is 3/((x+1)^2)