What is (\partial)/(\partial x)(4-2x^2-y^2) ?

The answer to (\partial)/(\partial x)(4-2x^2-y^2) is -4x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(4-2x^2-y^2)

\frac{\partial}{\partial x} (4 - 2 x^{2} - y^{2})

- 4 x

Solution steps

\frac{\partial}{\partial x} (4 - 2 x^{2} - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4) - \frac{\partial}{\partial x} (2 x^{2}) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (4) = 0

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 0 - 4 x - 0

Simplify

= - 4 x

What is (\partial)/(\partial x)(4-2x^2-y^2) ?
The answer to (\partial)/(\partial x)(4-2x^2-y^2) is -4x