What is the derivative of-3sin(2x-6cos(x)) ?

The derivative of-3sin(2x-6cos(x)) is -6cos(2x)+6sin(x)

What is the first derivative of-3sin(2x-6cos(x)) ?

The first derivative of-3sin(2x-6cos(x)) is -6cos(2x)+6sin(x)

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\frac{d}{d x} (- 3 sin (2 x) - 6 cos (x))

- 6 cos (2 x) + 6 sin (x)

Solution steps

\frac{d}{d x} (- 3 sin (2 x) - 6 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 sin (2 x)) - \frac{d}{d x} (6 cos (x))

\frac{d}{d x} (3 sin (2 x)) = 6 cos (2 x)

\frac{d}{d x} (6 cos (x)) = - 6 sin (x)

= - 6 cos (2 x) - (- 6 sin (x))

Simplify

= - 6 cos (2 x) + 6 sin (x)

What is the derivative of-3sin(2x-6cos(x)) ?
The derivative of-3sin(2x-6cos(x)) is -6cos(2x)+6sin(x)
What is the first derivative of-3sin(2x-6cos(x)) ?
The first derivative of-3sin(2x-6cos(x)) is -6cos(2x)+6sin(x)