Solution
Solution
Solution steps
Solve Bernoulli ODE:
Graph
Popular Examples
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Frequently Asked Questions (FAQ)
What is the solution for 2yy^'+2=y^2+2x ?
The solution for 2yy^'+2=y^2+2x is y=sqrt(-2x+c_{1)e^x},y=-sqrt(-2x+c_{1)e^x}