What is the tangent of f(x)=x^3-x,\at x=1 ?

The tangent of f(x)=x^3-x,\at x=1 is y=2x-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=x^3-x,\at x=1

tangent of

f (x) = x^{3} - x, at x = 1

y = 2 x - 2

Solution steps

Find the tangent point:

(1, 0)

Find the slope of

f (x) = x^{3} - x : \frac{df ( x )}{d x} = 3 x^{2} - 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(1, 0) : y = 2 x - 2

y = 2 x - 2

What is the tangent of f(x)=x^3-x,\at x=1 ?
The tangent of f(x)=x^3-x,\at x=1 is y=2x-2