What is the integral of 1/(x^{4/3)} ?

The integral of 1/(x^{4/3)} is -3/(x^{1/3)}+C

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integral of 1/(x^{4/3)}

\int \frac{1}{x ^{\frac{4}{3}}} d x

- \frac{3}{x ^{\frac{1}{3}}} + C

Solution steps

\int \frac{1}{x ^{\frac{4}{3}}} d x

Apply the Power Rule

= - \frac{3}{x ^{\frac{1}{3}}}

Add a constant to the solution

= - \frac{3}{x ^{\frac{1}{3}}} + C

What is the integral of 1/(x^{4/3)} ?
The integral of 1/(x^{4/3)} is -3/(x^{1/3)}+C