What is the derivative of (x^2-1/(x^4-1)) ?

The derivative of (x^2-1/(x^4-1)) is -(2x)/((x^2+1)^2)

What is the first derivative of (x^2-1/(x^4-1)) ?

The first derivative of (x^2-1/(x^4-1)) is -(2x)/((x^2+1)^2)

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\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{4} - 1})

- \frac{2 x}{( x ^{2} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{4} - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 1 ) ( x ^{4} - 1 ) - \frac{d}{d x} ( x ^{4} - 1 ) ( x ^{2} - 1 )}{( x ^{4} - 1 ) ^{2}}

\frac{d}{d x} (x^{2} - 1) = 2 x

\frac{d}{d x} (x^{4} - 1) = 4 x^{3}

= \frac{2 x ( x ^{4} - 1 ) - 4 x ^{3} ( x ^{2} - 1 )}{( x ^{4} - 1 ) ^{2}}

Simplify

\frac{2 x ( x ^{4} - 1 ) - 4 x ^{3} ( x ^{2} - 1 )}{( x ^{4} - 1 ) ^{2}} : - \frac{2 x}{( x ^{2} + 1 ) ^{2}}

= - \frac{2 x}{( x ^{2} + 1 ) ^{2}}

What is the derivative of (x^2-1/(x^4-1)) ?
The derivative of (x^2-1/(x^4-1)) is -(2x)/((x^2+1)^2)
What is the first derivative of (x^2-1/(x^4-1)) ?
The first derivative of (x^2-1/(x^4-1)) is -(2x)/((x^2+1)^2)