What is the integral of (x^3)/((1+x^4)^{1/3)} ?

The integral of (x^3)/((1+x^4)^{1/3)} is 3/8 (1+x^4)^{2/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (x^3)/((1+x^4)^{1/3)}

\int \frac{x ^{3}}{( 1 + x ^{4} ) ^{\frac{1}{3}}} d x

\frac{3}{8} (1 + x^{4})^{\frac{2}{3}} + C

Solution steps

\int \frac{x ^{3}}{( 1 + x ^{4} ) ^{\frac{1}{3}}} d x

Apply u-substitution

= \int \frac{1}{4 u ^{\frac{1}{3}}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int \frac{1}{u ^{\frac{1}{3}}} d u

Apply the Power Rule

= \frac{1}{4} \cdot \frac{3}{2} u^{\frac{2}{3}}

Substitute back

u = 1 + x^{4}

= \frac{1}{4} \cdot \frac{3}{2} (1 + x^{4})^{\frac{2}{3}}

Simplify

\frac{1}{4} \cdot \frac{3}{2} (1 + x^{4})^{\frac{2}{3}} : \frac{3}{8} (1 + x^{4})^{\frac{2}{3}}

= \frac{3}{8} (1 + x^{4})^{\frac{2}{3}}

Add a constant to the solution

= \frac{3}{8} (1 + x^{4})^{\frac{2}{3}} + C

What is the integral of (x^3)/((1+x^4)^{1/3)} ?
The integral of (x^3)/((1+x^4)^{1/3)} is 3/8 (1+x^4)^{2/3}+C