What is the integral of (-t)/((t+1)-sqrt(t+1)) ?

The integral of (-t)/((t+1)-sqrt(t+1)) is -t-1-2sqrt(t+1)+C

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integral of (-t)/((t+1)-sqrt(t+1))

\int \frac{- t}{( t + 1 ) - t + 1} d t

- t - 1 - 2 t + 1 + C

Solution steps

\int \frac{- t}{t + 1 - t + 1} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{t}{t + 1 - t + 1} d t

Apply u-substitution

= - \int 2 (u + 1) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int u + 1 d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - 2 (\int u d u + \int 1 d u)

\int u d u = \frac{u ^{2}}{2}

\int 1 d u = u

= - 2 (\frac{u ^{2}}{2} + u)

Substitute back

u = t + 1

= - 2 (\frac{( t + 1 ) ^{2}}{2} + t + 1)

Simplify

- 2 (\frac{( t + 1 ) ^{2}}{2} + t + 1) : - t - 1 - 2 t + 1

= - t - 1 - 2 t + 1

Add a constant to the solution

= - t - 1 - 2 t + 1 + C

What is the integral of (-t)/((t+1)-sqrt(t+1)) ?
The integral of (-t)/((t+1)-sqrt(t+1)) is -t-1-2sqrt(t+1)+C