(4x-3y)dx+(2y-3x)dy=0

解答

(4 x - 3 y) d x + (2 y - 3 x) d y = 0

y = \frac{3 x + x ^{2} + c _{1}}{2}, y = \frac{3 x - x ^{2} + c _{1}}{2}

求解步骤

(4 x - 3 y) d x + (2 y - 3 x) d y = 0

求解恰当方程:

y = \frac{3 x + x ^{2} + c _{1}}{2}, y = \frac{3 x - x ^{2} + c _{1}}{2}

y = \frac{3 x + x ^{2} + c _{1}}{2}, y = \frac{3 x - x ^{2} + c _{1}}{2}

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