What is the derivative of 9x^4+6x^3+1 ?

The derivative of 9x^4+6x^3+1 is 36x^3+18x^2

What is the first derivative of 9x^4+6x^3+1 ?

The first derivative of 9x^4+6x^3+1 is 36x^3+18x^2

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\frac{d}{d x} (9 x^{4} + 6 x^{3} + 1)

36 x^{3} + 18 x^{2}

Solution steps

\frac{d}{d x} (9 x^{4} + 6 x^{3} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x^{4}) + \frac{d}{d x} (6 x^{3}) + \frac{d}{d x} (1)

\frac{d}{d x} (9 x^{4}) = 36 x^{3}

\frac{d}{d x} (6 x^{3}) = 18 x^{2}

\frac{d}{d x} (1) = 0

= 36 x^{3} + 18 x^{2} + 0

Simplify

= 36 x^{3} + 18 x^{2}

What is the derivative of 9x^4+6x^3+1 ?
The derivative of 9x^4+6x^3+1 is 36x^3+18x^2
What is the first derivative of 9x^4+6x^3+1 ?
The first derivative of 9x^4+6x^3+1 is 36x^3+18x^2