What is the integral from 0 to pi/2 of tan^2(x) ?

The integral from 0 to pi/2 of tan^2(x) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to pi/2 of tan^2(x)

\int_{0}^{\frac{π}{2}} tan^{2} (x) d x

diverges

Solution steps

\int_{0}^{\frac{π}{2}} tan^{2} (x) d x

Rewrite using trig identities

= \int_{0}^{\frac{π}{2}} - 1 + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{\frac{π}{2}} 1 d x + \int_{0}^{\frac{π}{2}} sec^{2} (x) d x

\int_{0}^{\frac{π}{2}} 1 d x = \frac{π}{2}

\int_{0}^{\frac{π}{2}} sec^{2} (x) d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

What is the integral from 0 to pi/2 of tan^2(x) ?
The integral from 0 to pi/2 of tan^2(x) is diverges