What is the derivative of f(x)=x^3+5x+7 ?

The derivative of f(x)=x^3+5x+7 is 3x^2+5

What is the first derivative of f(x)=x^3+5x+7 ?

The first derivative of f(x)=x^3+5x+7 is 3x^2+5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

f (x) = x^{3} + 5 x + 7

3 x^{2} + 5

Solution steps

\frac{d}{d x} (x^{3} + 5 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (5 x) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (7) = 0

= 3 x^{2} + 5 + 0

Simplify

= 3 x^{2} + 5

What is the derivative of f(x)=x^3+5x+7 ?
The derivative of f(x)=x^3+5x+7 is 3x^2+5
What is the first derivative of f(x)=x^3+5x+7 ?
The first derivative of f(x)=x^3+5x+7 is 3x^2+5