What is (\partial}{\partial y}(\frac{3x)/y) ?

The answer to (\partial}{\partial y}(\frac{3x)/y) is -(3x)/(y^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial}{\partial y}(\frac{3x)/y)

\frac{\partial}{\partial y} (\frac{3 x}{y})

- \frac{3 x}{y ^{2}}

Solution steps

\frac{\partial}{\partial y} (\frac{3 x}{y})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 x \frac{\partial}{\partial y} (\frac{1}{y})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 x \frac{\partial}{\partial y} (y^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 x (- 1 \cdot y^{- 1 - 1})

Simplify

3 x (- 1 \cdot y^{- 1 - 1}) : - \frac{3 x}{y ^{2}}

= - \frac{3 x}{y ^{2}}

What is (\partial}{\partial y}(\frac{3x)/y) ?
The answer to (\partial}{\partial y}(\frac{3x)/y) is -(3x)/(y^2)