What is the f(x)=cos((ln(x+1))^2-e^{x^2}) ?

The f(x)=cos((ln(x+1))^2-e^{x^2}) is Domain: x>-1 Y Intercepts: (0,cos(-1)) Asymptotes: None

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f(x)=cos((ln(x+1))^2-e^{x^2})

f (x) = cos ((ln (x + 1))^{2} - e^{x^{2}})

Domain : x > - 1

Y Intercepts : (0, cos (- 1))

Asymptotes : None

Interval Notation

Domain : (- 1, \infty)

Solution steps

Domain of

cos (ln^{2} (x + 1) - e^{x^{2}}) : x > - 1

Axis interception points of

cos (ln^{2} (x + 1) - e^{x^{2}}) :

Y Intercepts

: (0, cos (- 1))

Asymptotes of

cos (ln^{2} (x + 1) - e^{x^{2}}) :

None

What is the f(x)=cos((ln(x+1))^2-e^{x^2}) ?
The f(x)=cos((ln(x+1))^2-e^{x^2}) is Domain: x>-1<br/>Y Intercepts: (0,cos(-1))<br/>Asymptotes: None