What is the tangent of f(x)=x^2,\at x=0.2 ?

The tangent of f(x)=x^2,\at x=0.2 is y=0.4x-0.04

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tangent of f(x)=x^2,\at x=0.2

tangent of

f (x) = x^{2}, at x = 0.2

y = 0.4 x - 0.04

Solution steps

Find the tangent point:

(0.2, 0.04)

Find the slope of

f (x) = x^{2} : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0.4

Find the line with slope m=

0.4

and passing through

(0.2, 0.04) : y = 0.4 x - 0.04

y = 0.4 x - 0.04

What is the tangent of f(x)=x^2,\at x=0.2 ?
The tangent of f(x)=x^2,\at x=0.2 is y=0.4x-0.04