What is (\partial)/(\partial x)(x^2e^y+x-2y) ?

The answer to (\partial)/(\partial x)(x^2e^y+x-2y) is 2e^yx+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(x^2e^y+x-2y)

\frac{\partial}{\partial x} (x^{2} e^{y} + x - 2 y)

2 e^{y} x + 1

Solution steps

\frac{\partial}{\partial x} (x^{2} e^{y} + x - 2 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2} e^{y}) + \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (2 y)

\frac{\partial}{\partial x} (x^{2} e^{y}) = 2 e^{y} x

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (2 y) = 0

= 2 e^{y} x + 1 - 0

Simplify

= 2 e^{y} x + 1

What is (\partial)/(\partial x)(x^2e^y+x-2y) ?
The answer to (\partial)/(\partial x)(x^2e^y+x-2y) is 2e^yx+1