What is (\partial)/(\partial y)(ln(x^3+1)+y^2) ?

The answer to (\partial)/(\partial y)(ln(x^3+1)+y^2) is 2y

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(\partial)/(\partial y)(ln(x^3+1)+y^2)

\frac{\partial}{\partial y} (ln (x^{3} + 1) + y^{2})

2 y

Solution steps

\frac{\partial}{\partial y} (ln (x^{3} + 1) + y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (ln (x^{3} + 1)) + \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (ln (x^{3} + 1)) = 0

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 0 + 2 y

Simplify

= 2 y

What is (\partial)/(\partial y)(ln(x^3+1)+y^2) ?
The answer to (\partial)/(\partial y)(ln(x^3+1)+y^2) is 2y