What is the derivative of (3x^2+x/(-x^2+3x-3)) ?

The derivative of (3x^2+x/(-x^2+3x-3)) is (10x^2-18x-3)/((-x^2+3x-3)^2)

What is the first derivative of (3x^2+x/(-x^2+3x-3)) ?

The first derivative of (3x^2+x/(-x^2+3x-3)) is (10x^2-18x-3)/((-x^2+3x-3)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (\frac{3 x ^{2} + x}{- x ^{2} + 3 x - 3})

\frac{10 x ^{2} - 18 x - 3}{( - x ^{2} + 3 x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x ^{2} + x}{- x ^{2} + 3 x - 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 x ^{2} + x ) ( - x ^{2} + 3 x - 3 ) - \frac{d}{d x} ( - x ^{2} + 3 x - 3 ) ( 3 x ^{2} + x )}{( - x ^{2} + 3 x - 3 ) ^{2}}

\frac{d}{d x} (3 x^{2} + x) = 6 x + 1

\frac{d}{d x} (- x^{2} + 3 x - 3) = - 2 x + 3

= \frac{( 6 x + 1 ) ( - x ^{2} + 3 x - 3 ) - ( - 2 x + 3 ) ( 3 x ^{2} + x )}{( - x ^{2} + 3 x - 3 ) ^{2}}

Expand

(6 x + 1) (- x^{2} + 3 x - 3) - (- 2 x + 3) (3 x^{2} + x) : 10 x^{2} - 18 x - 3

= \frac{10 x ^{2} - 18 x - 3}{( - x ^{2} + 3 x - 3 ) ^{2}}

What is the derivative of (3x^2+x/(-x^2+3x-3)) ?
The derivative of (3x^2+x/(-x^2+3x-3)) is (10x^2-18x-3)/((-x^2+3x-3)^2)
What is the first derivative of (3x^2+x/(-x^2+3x-3)) ?
The first derivative of (3x^2+x/(-x^2+3x-3)) is (10x^2-18x-3)/((-x^2+3x-3)^2)