What is the derivative of tan(xln(x)) ?

The derivative of tan(xln(x)) is sec^2(x)ln(x)+(tan(x))/x

What is the first derivative of tan(xln(x)) ?

The first derivative of tan(xln(x)) is sec^2(x)ln(x)+(tan(x))/x

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\frac{d}{d x} (tan (x) ln (x))

sec^{2} (x) ln (x) + \frac{tan ( x )}{x}

Solution steps

\frac{d}{d x} (tan (x) ln (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = tan (x), g = ln (x)

= \frac{d}{d x} (tan (x)) ln (x) + \frac{d}{d x} (ln (x)) tan (x)

\frac{d}{d x} (tan (x)) = sec^{2} (x)

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= sec^{2} (x) ln (x) + \frac{1}{x} tan (x)

\frac{1}{x} tan (x) = \frac{tan ( x )}{x}

= sec^{2} (x) ln (x) + \frac{tan ( x )}{x}

What is the derivative of tan(xln(x)) ?
The derivative of tan(xln(x)) is sec^2(x)ln(x)+(tan(x))/x
What is the first derivative of tan(xln(x)) ?
The first derivative of tan(xln(x)) is sec^2(x)ln(x)+(tan(x))/x