What is the tangent of f(x)=8sqrt(x),\at x=16 ?

The tangent of f(x)=8sqrt(x),\at x=16 is y=x+16

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tangent of f(x)=8sqrt(x),\at x=16

tangent of

f (x) = 8 x, at x = 16

y = x + 16

Solution steps

Find the tangent point:

(16, 32)

Find the slope of

f (x) = 8 x : \frac{df ( x )}{d x} = \frac{4}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(16, 32) : y = x + 16

y = x + 16

What is the tangent of f(x)=8sqrt(x),\at x=16 ?
The tangent of f(x)=8sqrt(x),\at x=16 is y=x+16