What is the derivative of f(x)=x^3+x^2 ?

The derivative of f(x)=x^3+x^2 is 3x^2+2x

What is the first derivative of f(x)=x^3+x^2 ?

The first derivative of f(x)=x^3+x^2 is 3x^2+2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

f (x) = x^{3} + x^{2}

3 x^{2} + 2 x

Solution steps

\frac{d}{d x} (x^{3} + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

= 3 x^{2} + 2 x

What is the derivative of f(x)=x^3+x^2 ?
The derivative of f(x)=x^3+x^2 is 3x^2+2x
What is the first derivative of f(x)=x^3+x^2 ?
The first derivative of f(x)=x^3+x^2 is 3x^2+2x