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Popular Calculus >

area x=2y^2,x=4+y^2

Solution

area

x = 2 y^{2}, x = 4 + y^{2}

Solution

No Solution

Solution steps

Isolate

y

for

x = 2 y^{2} : y = \frac{x}{2}, y = - \frac{x}{2}

Isolate

y

for

x = 4 + y^{2} : y = x - 4, y = - x - 4

f_{1} (x) = \frac{x}{2}

f_{2} (x) = - \frac{x}{2}

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{x}{2} = - \frac{x}{2} : x = 0

\frac{x}{2} = x - 4 : x = 8

\frac{x}{2} = - x - 4 :

No Solution for

x \in R

- \frac{x}{2} = x - 4 :

No Solution for

x \in R

- \frac{x}{2} = - x - 4 : x = 8

x - 4 = - x - 4 : x = 4

Curves not bounded

= No Solution

Graph

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Frequently Asked Questions (FAQ)

What is area x=2y^2,x=4+y^2 ?
The answer to area x=2y^2,x=4+y^2 is No Solution