derivative of (x+3/(8x^2e^x))

解

\frac{d}{d x} (\frac{x + 3}{8 x ^{2} e ^{x}})

- \frac{x ^{2} + 4 x + 6}{8 e ^{x} x ^{3}}

解答ステップ

\frac{d}{d x} (\frac{x + 3}{8 x ^{2} e ^{x}})

定数を除去:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d x} (\frac{x + 3}{x ^{2} e ^{x}})

商の法則を適用:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{8} \cdot \frac{\frac{d}{d x} ( x + 3 ) x ^{2} e ^{x} - \frac{d}{d x} ( x ^{2} e ^{x} ) ( x + 3 )}{( x ^{2} e ^{x} ) ^{2}}

\frac{d}{d x} (x + 3) = 1

\frac{d}{d x} (x^{2} e^{x}) = 2 x e^{x} + e^{x} x^{2}

= \frac{1}{8} \cdot \frac{1 \cdot x ^{2} e ^{x} - ( 2 x e ^{x} + e ^{x} x ^{2} ) ( x + 3 )}{( x ^{2} e ^{x} ) ^{2}}

簡素化

\frac{1}{8} \cdot \frac{1 \cdot x ^{2} e ^{x} - ( 2 x e ^{x} + e ^{x} x ^{2} ) ( x + 3 )}{( x ^{2} e ^{x} ) ^{2}} : - \frac{x ^{2} + 4 x + 6}{8 e ^{x} x ^{3}}

= - \frac{x ^{2} + 4 x + 6}{8 e ^{x} x ^{3}}