What is (\partial)/(\partial x)(L-x*cos(b)) ?

The answer to (\partial)/(\partial x)(L-x*cos(b)) is -cos(b)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(L-x*cos(b))

\frac{\partial}{\partial x} (L - x \cdot cos (b))

- cos (b)

Solution steps

\frac{\partial}{\partial x} (L - x cos (b))

Treat

L, b

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (L) - \frac{\partial}{\partial x} (x cos (b))

\frac{\partial}{\partial x} (L) = 0

\frac{\partial}{\partial x} (x cos (b)) = cos (b)

= 0 - cos (b)

Simplify

= - cos (b)

What is (\partial)/(\partial x)(L-x*cos(b)) ?
The answer to (\partial)/(\partial x)(L-x*cos(b)) is -cos(b)