What is the tangent of f(x)=4x^2+2x,\at x=2 ?

The tangent of f(x)=4x^2+2x,\at x=2 is y=18x-16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=4x^2+2x,\at x=2

tangent of

f (x) = 4 x^{2} + 2 x, at x = 2

y = 18 x - 16

Solution steps

Find the tangent point:

(2, 20)

Find the slope of

f (x) = 4 x^{2} + 2 x : \frac{df ( x )}{d x} = 8 x + 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 18

Find the line with slope m=

18

and passing through

(2, 20) : y = 18 x - 16

y = 18 x - 16

What is the tangent of f(x)=4x^2+2x,\at x=2 ?
The tangent of f(x)=4x^2+2x,\at x=2 is y=18x-16