What is the integral of arccos^2(x) ?

The integral of arccos^2(x) is xarccos^2(x)-2(arccos(x)sqrt(1-x^2)+x)+C

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integral of arccos^2(x)

\int arccos^{2} (x) d x

x arccos^{2} (x) - 2 (arccos (x) 1 - x^{2} + x) + C

Solution steps

\int arccos^{2} (x) d x

Apply Integration By Parts

= x arccos^{2} (x) - \int - \frac{2 x arccos ( x )}{1 - x ^{2}} d x

\int - \frac{2 x arccos ( x )}{1 - x ^{2}} d x = 2 (arccos (x) 1 - x^{2} + x)

= x arccos^{2} (x) - 2 (arccos (x) 1 - x^{2} + x)

Add a constant to the solution

= x arccos^{2} (x) - 2 (arccos (x) 1 - x^{2} + x) + C

What is the integral of arccos^2(x) ?
The integral of arccos^2(x) is xarccos^2(x)-2(arccos(x)sqrt(1-x^2)+x)+C