What is the integral of xe^{x^2-1}+x^2-1 ?

The integral of xe^{x^2-1}+x^2-1 is 1/2 e^{x^2-1}+(x^3)/3-x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of xe^{x^2-1}+x^2-1

\int x e^{x^{2} - 1} + x^{2} - 1 d x

\frac{1}{2} e^{x^{2} - 1} + \frac{x ^{3}}{3} - x + C

Solution steps

\int x e^{x^{2} - 1} + x^{2} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x e^{x^{2} - 1} d x + \int x^{2} d x - \int 1 d x

\int x e^{x^{2} - 1} d x = \frac{1}{2} e^{x^{2} - 1}

\int x^{2} d x = \frac{x ^{3}}{3}

\int 1 d x = x

= \frac{1}{2} e^{x^{2} - 1} + \frac{x ^{3}}{3} - x

Add a constant to the solution

= \frac{1}{2} e^{x^{2} - 1} + \frac{x ^{3}}{3} - x + C

What is the integral of xe^{x^2-1}+x^2-1 ?
The integral of xe^{x^2-1}+x^2-1 is 1/2 e^{x^2-1}+(x^3)/3-x+C