integral of (3x^2+4)^2

Lösung

\int (3 x^{2} + 4)^{2} d x

\frac{9 x ^{5}}{5} + 8 x^{3} + 16 x + C

Schritte zur Lösung

\int (3 x^{2} + 4)^{2} d x

Multipliziere aus

(3 x^{2} + 4)^{2} : 9 x^{4} + 24 x^{2} + 16

= \int 9 x^{4} + 24 x^{2} + 16 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 x^{4} d x + \int 24 x^{2} d x + \int 16 d x

\int 9 x^{4} d x = \frac{9 x ^{5}}{5}

\int 24 x^{2} d x = 8 x^{3}

\int 16 d x = 16 x

= \frac{9 x ^{5}}{5} + 8 x^{3} + 16 x

Füge eine Konstante zur Lösung hinzu

= \frac{9 x ^{5}}{5} + 8 x^{3} + 16 x + C

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